This example shows how to provision a Microsoft Exchange 2000 or Exchange 2003 resource mailbox object.
Attribute Inclusion List
You must select the following attributes from the Select Attributes property page for your Active Directory Domain Services (AD DS) management agent to provision an Exchange resource mailbox:
- mailNickname
- homeMDB
- msExchMailboxSecurityDescriptor
- msExchMasterAccountSid
- nTSecurityDescriptor
- userAccountControl
The following examples show how to provision an Exchange resource mailbox. You must add a reference to logging.dll to use the LogException method.
| Visual Basic |  Copy Code |
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Public Sub Provision(ByVal mventry As MVEntry) _
Implements IMVSynchronization.Provision
Dim adMA As ConnectedMA
Dim csentry As CSEntry
Dim nickName, mailboxMDB As String
Dim dn as ReferenceValue
Dim sid as byte()
try
adMA = mventry.ConnectedMAs("Fabrikam AD MA")
nickName = mventry("mailNickname").Value
mailboxMDB = mventry("homeMDB").Value
sid = mventry("objectSID").BinaryValue
' Construct the distinguished name.
dn = adMA.EscapeDNComponent("CN=" + mventry("cn").Value).Concat("ou=mailboxes,dc=fabrikam,dc=com")
If 0 = adMA.Connectors.Count then
csentry = ExchangeUtils.CreateMailbox(adMA, dn, nickName, mailboxMDB, sid)
End If
' Log and rethrow any exception.
Catch ex As Exception
Logging.Logging.LogException(ex, "Provision", "Caught exception", False)
Throw
End Try
End Sub
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| C# | Copy Code |
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void IMVSynchronization.Provision (MVEntry mventry)
{
ConnectedMA adMA;
CSEntry csentry;
String nickName, mailboxMDB;
ReferenceValue dn;
byte[] sid;
try
{
adMA = mventry.ConnectedMAs["Fabrikam AD MA"];
nickName = mventry["mailNickname"].Value;
mailboxMDB = mventry["homeMDB"].Value;
sid = mventry["objectSID"].BinaryValue;
// Construct the distinguished name.
dn = adMA.EscapeDNComponent("CN=" + mventry["cn"].Value).Concat("ou=mailboxes,dc=fabrikam,dc=com");
if(0 == adMA.Connectors.Count)
{
csentry = ExchangeUtils.CreateMailbox(adMA, dn, nickName, mailboxMDB, sid);
}
}
// Log and rethrow any exception.
catch(Exception ex)
{
Logging.Logging.LogException(ex, "Provision", "Caught exception", false);
throw;
}
}
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