Microsoft Identity Integration Server 2003 Developer Reference

Example: Mailbox

This example shows how to provision an Exchange 2000 or Exchange 2003 mailbox object.

Attribute Inclusion List

You must select the following attributes from the Select Attributes property page for your Active Directory management agent to provision an Exchange mailbox:

The following example shows how to provision an Exchange mailbox. Be sure to add a reference to logging.dll to use the LogException method.

[Visual Basic .NET] 
Public Sub Provision(ByVal mventry As MVEntry) _
	Implements IMVSynchronization.Provision

	Dim adMA As ConnectedMA
	Dim csentry As CSEntry
	Dim nickName, mailboxMDB As String
	Dim dn as ReferenceValue

	try
		adMA = mventry.ConnectedMAs("Fabrikam AD MA")

		nickName   = mventry("mailNickname").Value
		mailboxMDB = mventry("homeMDB").Value

		' Construct the distinguished name
		dn = adMA.EscapeDNComponent("CN=" + mventry("cn").Value).Concat("ou=mailboxes,dc=fabrikam,dc=com")

		If 0 = adMA.Connectors.Count then
			csentry = ExchangeUtils.CreateMailbox(adMA, dn, nickName, mailboxMDB)
		End If

		' Log and rethrow any exception
		Catch ex As Exception
			Logging.Logging.LogException(ex, "Provision", "Caught exception", False)
			Throw
	End Try
End Sub
[C#] 
void IMVSynchronization.Provision (MVEntry mventry)
{
	ConnectedMA adMA;
	CSEntry csentry;
	String nickName, mailboxMDB;
	ReferenceValue dn;

	try
	{
		adMA = mventry.ConnectedMAs["Fabrikam AD MA"];

		nickName   = mventry["mailNickname"].Value;
		mailboxMDB = mventry["homeMDB"].Value;

		// Construct the distinguished name
		dn = adMA.EscapeDNComponent("CN=" + mventry["cn"].Value).Concat("ou=mailboxes,dc=fabrikam,dc=com");

		if(0 == adMA.Connectors.Count)
		{
			csentry = ExchangeUtils.CreateMailbox(adMA, dn, nickName, mailboxMDB);
	}
}

	// Log and rethrow any exception
	catch(Exception ex)
	{
		Logging.Logging.LogException(ex, "Provision", "Caught exception", false);
		throw;
}
}

See Also

CreateMailbox(ConnectedMA,ReferenceValue,String,String)