Microsoft Identity Integration Server 2003 Developer Reference |
This example shows how to provision an Exchange 2000 or Exchange 2003 resource mailbox object.
You must select the following attributes from the Select Attributes property page for your Active Directory management agent to provision an Exchange resource mailbox:
The following example shows how to provision an Exchange resource mailbox. Be sure to add a reference to logging.dll to use the LogException method.
Public Sub Provision(ByVal mventry As MVEntry) _ Implements IMVSynchronization.Provision Dim adMA As ConnectedMA Dim csentry As CSEntry Dim nickName, mailboxMDB As String Dim dn as ReferenceValue Dim sid as byte() try adMA = mventry.ConnectedMAs("Fabrikam AD MA") nickName = mventry("mailNickname").Value mailboxMDB = mventry("homeMDB").Value sid = mventry("objectSID").BinaryValue ' Construct the distinguished name dn = adMA.EscapeDNComponent("CN=" + mventry("cn").Value).Concat("ou=mailboxes,dc=fabrikam,dc=com") If 0 = adMA.Connectors.Count then csentry = ExchangeUtils.CreateMailbox(adMA, dn, nickName, mailboxMDB, sid) End If ' Log and rethrow any exception Catch ex As Exception Logging.Logging.LogException(ex, "Provision", "Caught exception", False) Throw End Try End Sub
void IMVSynchronization.Provision (MVEntry mventry) { ConnectedMA adMA; CSEntry csentry; String nickName, mailboxMDB; ReferenceValue dn; byte[] sid; try { adMA = mventry.ConnectedMAs["Fabrikam AD MA"]; nickName = mventry["mailNickname"].Value; mailboxMDB = mventry["homeMDB"].Value; sid = mventry["objectSID"].BinaryValue; // Construct the distinguished name dn = adMA.EscapeDNComponent("CN=" + mventry["cn"].Value).Concat("ou=mailboxes,dc=fabrikam,dc=com"); if(0 == adMA.Connectors.Count) { csentry = ExchangeUtils.CreateMailbox(adMA, dn, nickName, mailboxMDB, sid); } } // Log and rethrow any exception catch(Exception ex) { Logging.Logging.LogException(ex, "Provision", "Caught exception", false); throw; } }
CreateMailbox(ConnectedMA,ReferenceValue,String,String,Byte[])